Coin Change 2 Program (Leetcode):
You are given an integer array coins
representing coins of different denominations and an integer amount
representing a total amount of money.
Return the number of combinations that make up that amount. If that amount of money cannot be made up by any combination of the coins, return 0
.
You may assume that you have an infinite number of each kind of coin.
The answer is guaranteed to fit into a signed 32-bit integer.
Example 1:
Input: amount = 5, coins = [1,2,5] Output: 4 Explanation: there are four ways to make up the amount: 5=5 5=2+2+1 5=2+1+1+1 5=1+1+1+1+1
Example 2:
Input: amount = 3, coins = [2] Output: 0 Explanation: the amount of 3 cannot be made up just with coins of 2.
Example 3:
Input: amount = 10, coins = [10] Output: 1
Constraints:
1 <= coins.length <= 300
1 <= coins[i] <= 5000
- All the values of
coins
are unique. 0 <= amount <= 5000
dp = [0 for i in range(amount + 1)]
dp[0] = 1
for i in coins:
for j in range(1, amount + 1):
if i <= j:
dp[j] += dp[j - i]
print(dp[amount] if dp[amount] != 0 else 0)
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